A boy of mass 50kg running at 5ms-¹ jumps on to a trolly of 20kg travelling in the same direction at 1.5ms-1 . Find their common velocity.
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Answered by
4
Given:
m1 = 50 kg
v1 = 5 m/s [E]
m2 = 20 kg
v2 = 1.5 m/s [E]
v3 = final velocity
Formula:
m1v1 + m2v2 = (m1 + m2) x v3
We need to find v3
v3 = (m1v1 + m2v2) / (m1 + m2)
= (50x5 + 20x1.5) / (50 + 20)
= 280 / 70
= 4 m/s [E]
The final velocity is 4 m/s [E].
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Answered by
29
Answer:
m1 = 50 kg
v1 = 5 m/s [E]
m2 = 20 kg
v2 = 1.5 m/s [E]
v3 = final velocity
Formula:
m1v1 + m2v2 = (m1 + m2) x v3
We need to find v3
v3 = (m1v1 + m2v2) / (m1 + m2)
= (50x5 + 20x1.5) / (50 + 20)
= 280 / 70
= 4 m/s [E]
The final velocity is 4 m/s [E].
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