A boy of mass 55kg skips at the rate of 15 steps per minute through an average height of 25cm. calculate the power developed .
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m = 55kg
t = 1 minute = 60 sec
g = 10 m/s^2
h = 25 cm = 0.25 m ( 1m = 100cm )
Power= Work / time
= Fs / t
= mgh / t ( F=ma=mg , s=h )
= 55 * 10 * 0.25 * 15 / 60 ( 15 is multiply because the action is done 15 times )
= 34.3 watt
Therefore , the total power developed is 34.3 watt
____Welcome____
t = 1 minute = 60 sec
g = 10 m/s^2
h = 25 cm = 0.25 m ( 1m = 100cm )
Power= Work / time
= Fs / t
= mgh / t ( F=ma=mg , s=h )
= 55 * 10 * 0.25 * 15 / 60 ( 15 is multiply because the action is done 15 times )
= 34.3 watt
Therefore , the total power developed is 34.3 watt
____Welcome____
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