Question

A boy of mass 60 kg is holding a vertical rope, the rope breaks if the mass of 75 kg is suspended from it. What is the maximum acceleration of the boy with which it can climb the rope?​

Answer 1

Hello Dear,

◆ Answer -

a = 2.5 m/s^2

◆ Explaination -

Maximum tension the rope can bear is -

T = 75 × g

T = 75 × 10

T = 750 N ...(1)

Let a be maximum acceleration boy can climb.

T = 60 (a + g)

T = 60 (a + 10) ...(2)

From (1) & (2),

750 = 60 (a + 10)

a + 10 = 12.5

a = 12.5 - 10

a = 2.5 m/s^2

Therefore, maximum acceleration with which the boy can climb is 2.5 m/s^2.

Thanks dear...