Question

a boy of mass 60 kg is holding a vertical rope the rope can break when mass of 75 kg is suspended from it the maximum acceleration with which the boy can climb the rope without breaking it is

Answer 1

Answer:

0.25 m/s^2.

Explanation:

The tension in the string or the breaking force of the string will be 75g N. So, on making a free body diagram, the boy who is having a weight of 60g will pull the string down with an acceleration a.

So, Tension or breaking stress =m(g+a) or 75g=60g+60a which on solving we will get that a=15/60 or 1/4 = 0.25 m/s^2. So, the maximum acceleration with which the boy can climb the rope is 0.25 m/s^2.