A boy of mass 60 kg running at 3 m/s jumps on to a trolley of mass 140 moving with a velocity of 1.5 m/s in the same direction. What is their common velocity?
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4
Answer:
your answer is the velocity in between them is2.7m/sec²
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⏩ * For boy: m1 = 60 kg, u1= 3 m/s, v1= v (say)
* For trolley: m2= 140 kg, u2= 1.5 m/s, v2= v
Now, by conservation of momentum,
m1u1 + m2u2 = (m1 + m2) v
= 60 × 3 + 140 × 1.5 = (60 + 140) v
or
v= 180 + 210/ 200 = 390/200
= 1.95 m/s. Ans.
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