Question

A boy of mass 60 kg running at 3 m/s jumps on to a trolley of mass 140 kg moving with velocity of 1.5 m/s in the same direction. With what velocity will the two moves together?​

Answer 1

Answer:-

• 1.95m/s is the required answer

Explanation :-

According to the Question

It is given that ,

• Mass of Boy (m₁) = 60kg
• Initial velocity ,(u₁) = 3m/s
• Mass of trolley (m₂) = 140kg
• Initial velocity (u₂) = 1.5m/s

And both are moving in same direction .

We have to calculate the combined velocity .

Since, the combined mass of the system is 60+140 = 200kg

Let the combined velocity be v m/s.

Using Momentum Formula .

• m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

➻ m₁u₁ + m₂u₂ = mv

substitute the value we get

➻ (60×3) + (140×1.5) = 200×v

➻ 180 + 210 = 200×v

➻ 390 = 200×v

➻ 390/200 = v

➻ v = 390/200

➻ v = 1.95m/s

• Hence, the combined velocity of the system is 1.95m/s.

Answer 2

Answer:

$\underline{\purple{\ddot{\MasterRohith}}}$

Given:-

• A boy of mass 60kg running at 3 m/s jumps on a trolley of mass 140kg moving with the velocity of 1.5m/s in the same direction .

To prove :-

• With what velocity will the two moves together.

Explanation :-

• First here we should calculate combined velocity .

• Therefore, here combined mass of the given system

• which is 60kg+140kg=200kg

Now , here we should use momentum formula,

that is ,

• m1u1+m2u2=m1v1+m2v2
• m1u1+m2u2=mv(mv is the combined mass of the system)

• (60×3)+ (140×1.5)=200×v.

• 180+210=200×v
• 390= 200×v
• 390/200=v
• v=1.95 m/s.

Therefore, at 1.95m/s the velocity moves together.

Hope it helps u mate.

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