A boy of mass 60kg runs up a set of steps of total height 3m.workdone in joule is?g =10m/s^2
Answers
Explanation:
since 1joule= netwon/ meter
Given data : A boy of mass 60 kg runs up a set of steps of total height 3 m. {g = 10 m/s²}
Solution :
- Mass of the boy, m = 60 kg
- Total height of steps, h = 3 m
- Acceleration due to gravity, g = 10 m/s²
Now,
➜ Work done = force * displacement
and
➜ Force = mass * acceleration
A/C to given data, acceleration due to gravity, g is 10 m/s².
∴ Force = mass * acceleration due to gravity
Now,
➜ Work done = mass * acceleration due to gravity * displacement
A/C to given data, boy runs up a set of steps of total height 3 m hence displacement is 3m.
➜ Work done = 60 * 10 * 3
➜ Work done = 600 * 3
➜ Work done = 1800 Joule
Answer : Hence, the work done is 1800 joule.
More info :
- Work has only a magnitude but no direction. The formula for work is written as a dot product of force and displacement.
- Force is stated as a vector quantity, meaning it has elements of both magnitude and direction.
- Displacement is an example of a vector quantity.
- A vector is any quantity with both magnitude and direction
Formula :
- Work done but a force acting on a body, W = F • s = Fs cos θ
where,
- W = work done
- F = force
- s = displacement
- cos θ = the cosine of the angle θ between them.
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