A boy of mass kg running at 3 metre per second jump onto a trolley of mass 140 kg moving with a velocity of 1. 5 m per second in the same direction calculate the final velocity
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as in this question we have to conserve momentum because net external force is zero here . so apply M1V1 +M2V2 = (M1+M2)*Vfinal
so Vf=( 1*3+140*1.5) ÷141 m/s
so Vf=( 1*3+140*1.5) ÷141 m/s
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the answer will be zero
ankitiitismgmailcom:
not zero
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