Question

A boy of mass m is moving in a circle of radius r with a constant speed v. The force on the body is mv^2/r and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle?

please answer the question correctly ​

Answer 1

Answer:

A boy of mass m is moving in a circle of radius r with a constant speed v. The force on the body is mv^2/r and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle?

please answer the question correctly

Answer 2

Answer:zero

Explanation:as work done is

Force*displacement*cos@

@=90 degrees alwasys to the force

From formula

MV(squar)/r*2r*cos90

Cos90 is zero

So work done is zero

Note angle is between force {centripetal force} and displacement{ tangential displacement}