a boy of mass 'm' is moving with a uniform velocity 'u' . A force applied on the body due to which its velocity changes from 'u' to 'v' . How much work is being done by the force?
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Work done = Force × Displacement
W = Mass × Acceleration × Displacement
W= M × (V-U)/T × L
Where , 'W' is work done , 'V' is Final velocity , 'U' is Initial velocity , 'T' is time taken and 'L' refers to the Displacement
W = Mass × Acceleration × Displacement
W= M × (V-U)/T × L
Where , 'W' is work done , 'V' is Final velocity , 'U' is Initial velocity , 'T' is time taken and 'L' refers to the Displacement
Answered by
1
Work done = Force × Displacement
Work done = Mass × Acceleration × Displacement
Work done= M × (V-U)/T × L
Work done = Mass × Acceleration × Displacement
Work done= M × (V-U)/T × L
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