Question

A boy of mass m is sliding down a vertical pole by pressing it with a horizontal force f. If is the coefficient of friction between his palms and the pole, then the acceleration with which he slides down will beg

Answer 1

Answer:

SOLUTION

Here, normal reaction, R=f

Therefore, force of friction, fr=μR=μf

Net downward force, F=mg−fr=mg−μf

From Newton's second law of motion, acceleration, a=Fm=mg−μfm=g−μfm

Hence, the correct choice is (d).

g−μfm