Question

A BOY OF WEIGHT 45 kgf
STANDS ON A PLATFORM OF
DIMENSIONS 1.5 cm X 0.4 cm. THE
PRESSURE IN PASCALS WILL BE :
​

Answer 1

Answer:

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Explanation:

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Answer 2

Given:

A BOY OF WEIGHT 45 kgf STANDS ON A PLATFORM OF DIMENSIONS 1.5 cm X 0.4 cm.

To find:

Pressure in Pascal units

Calculation:

Pressure is given by the perpendicular force on the surface divided by the surface area upon which the force acts.

$\rm{pressure = \dfrac{force}{area} }$

$= > \rm{pressure = \dfrac{45 \times g}{ \frac{1.5}{100} \times \frac{0.4}{100} } }$

$= > \rm{pressure = \dfrac{45 \times g}{ \frac{1.5 \times 0.4}{ {(100)}^{2} } } }$

$= > \rm{pressure = \dfrac{45 \times 10}{ \frac{1.5 \times 0.4}{ {(10)}^{4} } } }$

$= > \rm{pressure = \dfrac{45 \times {10}^{5} }{ 1.5 \times 0.4} }$

$= > \rm{pressure = \dfrac{45 \times {10}^{5} }{ 0.6} }$

$= > \rm{pressure = \dfrac{45 \times {10}^{6} }{ 6} }$

$= > \rm{pressure = 7.5 \times {10}^{6} \: pascal }$

So, final answer is:

$\boxed{\bf{pressure = 7.5 \times {10}^{6} \: pascal }}$