A boy of weight 60 kg wt is standing in a lift. If the lift begins to move up with a uniform speed 4.9 m/s, the apparent weight of boy is
1)60 kg wt
2)90 kg wt
3)30 kg wt
4) zero
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Given:
A boy of weight 60 kg wt is standing in a lift. If the lift begins to move up with a uniform speed 4.9 m/s.
To find:
Apparent weight of the boy?
Calculation:
- As per the question, the weight of boy = 60 kgwt with respect to a stationary lift.
Now, the lift moves upwards with a uniform speed of 4.9 m/s.
- That means the boy doesn't experience any additional acceleration of the lift.
- In other words, does not experience any pseudo-force.
- Apparent weight = 0 + 60 = 60 kgwt.
Hence, his apparent weight will remain same as 60 kgwt.
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