Question

A boy on a 78.4high cliff drops a stone . One second later he throws another stone downwards with some speed. The two stones reach the ground simultaneously. Find the speed with which the second stone was thrown

Answer 1

Answer:

Around 11m/s

Explanation:

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T1 = time for the first stone

T2 = time for second stone = T1 - 1

V = velocity of the second stone

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78.4 = 1/2(10)(t1)2

T1 = 4s

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78.4 = u(3) + 1/2(10)(9)

U = 11m/s

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Please mark as brainliest and feel free to ask for any clarification

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