A boy on a bicycle drags a wagon full of newspapers at 0.80 m/s for 30 min using force of 40 N. how much work he ha the boy done
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Answer:
★W (work) = ? (in Joule ou kg.m²/s²)
★F (force) = 40 N (or 40 kg.m/s²)
★d (distance) = ? (in m)
★s (average speed) = 0.800 m/s
★t (time) = 30 min = 30*(60sec) = 1800 s
Apply the data to the average speed formula, we will have:
S = \dfrac{d}{t}S=
t
d
d = S×td=S×t
d = 0.800\:\dfrac{m}{\diagup\!\!\!\!s} *1800\:\diagup\!\!\!\!sd=0.800
╱s
m
∗1800╱s
\boxed{d = 1440\:m}\Longleftarrow(distance)
d=1440m
⟸(distance)
Applying the Force formula parallel to the displacement, we have the following work:
W = F × dW=F×d
W = 40\:kg×\dfrac{m}{s^2} ×1440\:mW=40kg×
s
2
m
×1440m
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