Question

A boy on a bicycle increases his velocity from 5 m/s to 20m/s in 10 seconds.

a)What is the acceleration of the bicycle?
b) what distance was covered by the bicycle during the 10 seconds?

Answer 1

Answer:

(a) a=1.5m/s2

(b) d=ut+1/2at2

d= 5×10+1/2×1.5×100

d=50+75

d=125m

hope ,it may help u

Answer 2

Answer:

The acceleration is 1.5 m/s² and distance is 125 m.

Explanation:

As per the data given in the question,

We have,

Initial velocity of the bicycle(u)- 5 m/s

Final velocity of the bicycle(v)- 10 m/s

Time taken to increase the speed- 10 sec

Now,

(a) Acceleration= ?

using formula

$v=u+at\\20=5+a\times10\\15=a\times10\\s=1.5 \:m/s^{2}$

(b) Distance covered= ?

$v^{2} -u^{2} =2as\\20^{2}- 5^{2}= 2\times1.5\times s\\ 400-25=3s\\375=3s\\s=125\: m$

Hence, the acceleration is 1.5 m/s² and distance is 125 m.

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