Question

A boy opens a nut by applying a force of 150 N using a wrench of length 30cm . If he wants to open it by a force of 50 N , what should be the length of wrench ?

Answer 1

Answer:

F = 150 N

D= 30cm = 0.3m

the moment of force required= F× D

= 150× 0.3m

= 45Nm

length=D=?

Moment of force = Force × Distance

= 45Nm= 50N × D

= D= 45/ 50m

= 0.9m or 90cm

Answer 2

$\huge\mathfrak\red{☛Solution♡}$

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Given,

✧Force F = 150 N

✧Distance d = 30 cm => 0.3 m

☞Moment of force required

➫ F × d

➫ 150 N × 0.3 m

➫ 45 Nm

Now, if

✦Force F = 50 N

✦Moment of needed = 45 Nm

✦Length d = ?

☞ᴍᴏᴍᴇɴᴛ ᴏғ ғᴏʀᴄᴇ = ғᴏʀᴄᴇ × ᴅɪsᴛᴀɴᴄᴇ

$➱ 45 \: Nm = 50N \times d$

$➱ d = \frac{45}{50} m$

$➱d \: = 0.9 m\:(or \: 90cm)$

Hence , the length of wrench is 0.9m or 90 cm

$\blue{╍╍╍╍╍╍╍╍╍★★★╍╍╍╍╍╍╍╍╍}$