A boy opens a nut by applying a force of 200 N using a wrench of length 10 cm. If he wants to open it by a force of 50 N, what should be the length of wrench?
Answers
Answered by
7
Answer:
Given
F1 = 150N
l1 = 0.4m
F2 = 60N
l2 = ?
Since, Force x perpendicular distance = constant
F1 x l1 = F2 x l2
150 x 0.4 = 60 x l2
l2 = 1 m
Explanation:
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Answered by
0
Answer:
Given
F1 = 150N
l1 = 0.4m
F2 = 60N
l2 = ?
Since, Force x perpendicular distance = constant
F1 x l1 = F2 x l2
150 x 0.4 = 60 x l2
l2 = 1 m
Explanation:
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