Question

- A boy playing on the roof of a 10 m high building
throws a ball with a speed of 10 m/s at an angle of
30° with the horizontal. How far from the throwing point
will the ball be at the height of 10 m from the ground?​

Answer 1

Explanation:

We have to simply calculate the range of projectile.

R=

g

u

2

sin2θ

=

10

(10)

2

sin(2×30

o

)

=5

3

=8.66m