A boy playing on the roof of a 10m high building throws a ball with a speed of 10m/s at an angle 30° with the horizontal . How far from the throwing point will the ball be at the height of 10m from the ground ?
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Explanation:- The ball will be at point P when it is at height of height of 10m from the ground . so , we have to find the distance op , which van be calculated directly by considering it as a projectile on a levelled plane (OX)
- OP = R = u²sin2¢ /g
- = 10² × sin (2*30°)/10
- = 10×√3/2
- = 5√3 = 8.66 m Answer
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