A boy pull a toy car with a force of 50n threw a sting which make an angle of 30degee with horizontal if a toy moves a distance 1m horizontal what is the amount of work done
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The Force vector is making a angle of 30° with the horizontal. Therefore, the horizontal component of the Force vector will be Fcos∅.
Work done = Force × displacement
W = Fcos∅ × s
W = 50cos30° × 1
W = 50 × (√3)/2
W = 25√3J
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