Question

A boy pulls a box of mass 48kg with a force of 110N at an angle of 28° above the horizontal. The coefficient of friction between the sled and the surface is 0.32. Determine the work done if it's pulled 5.5m.

Answer 1

Answer:-

Given, Mass of the box =5Kg,

Coefficient of kinetic frictionμ=0.5

Displacement =10cm

Since box moves with constant velocity means acceleration = 0

Force appliedF= Frictional force =μ×mg = 25 N

work done by force=F×S=25×0.1=2.5J

Applying work-energy theorem

Wfriction​+Wforce​=ΔKE

Since no change in velocity so ΔKE=0

hence Wfriction​=−Wforce​=−2.5J

Hope it helps..!!

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