Question

A boy pulls a toy with force of 50w through a string. which makes an angle of 30 degree with the horizontal so as to move toy by a distance of 1m horizontally, what is the amount as work done?

Answer 1

❥︎ANSWER

Given

F = 50N

θ = 30

s = 1m

Work done = F × S × cosθ

= 50N × 1N × cos30

= 50 × 1 × 0.866j

= 43.3j

\text{Second\;situation\;when\;force\;applied\;at\;angle\; of\;45}

Work done = F × S × cosθ

43.3j = F × S × cos45

43.3j = F × 1m × cos45

\tt{\rightarrow F=\dfrac{43.3j}{1m\times cos45}}→F=1m×cos4543.3j

\tt{\rightarrow\dfrac{43.3mm}{0.707m}}→0.707m43.3mm

= 61.2N

❥︎THANKS

I hope it will help you.