Question

a boy pushes a book by applying a force of 40N . find the work done by this force as the book is displaced through 25 cm along the path.​

Answer 1

Answer:

• Work Done (W) is 10 Joules.

Given:

1. Force Applied (F) = 40 N.
2. Distance travelled (s) = 25 cm.

Explanation:

$\rule{300}{1.5}$

From Work Done Formula,

$\large\bigstar \: {\boxed{\tt W = F.s}}$

$\bold{Here}\begin{cases}\text{F Denotes Applied Force} \\ \text{s Denotes Distance covered} \\ \text{W Denotes Work Done}\end{cases}$

Now,

$\large{\boxed{\tt W = F.s}}$

Substituting the values,

$\longmapsto \large{\tt W = 40 \: N \times 25 \: cm}$

As the units is given in cm we need to convert it into meters.

∵ [1 cm = 10⁻² m]

Substituting.

$\longmapsto \large{\tt W = 40 \: N \times 25 \times 10^{-2} \: m}$

$\longmapsto \large{\tt W = 40 \times 25 \times 10^{-2}}$

$\longmapsto \large{\tt W = 10 \times 100 \times 10^{-2}}$

$\longmapsto \large{\tt W = 10 \times 10^2 \times 10^{-2}}$

$\longmapsto \large{\tt W = 10 \times \cancel{10^2} \times \cancel{10^{-2}}}$

$\longmapsto \large{\tt W = 10 \times 1}$

$\longmapsto \large{\underline{\boxed{\red{\tt W = 10 \: J}}}}$

∴ Work Done (W) by the Boy is 10 Joules.

$\large\boxed{\begin{minipage}{7 cm} \bigstar \: \large{\underline{\underline{\tt Important \: Formulas}}}: \\\\ \star \: \tt W = F.s \\\\ \star \: \tt K.E = \dfrac{1}{2}Mv^2 \\\\ \star \: \tt P.E = mgh \\\\ \star \: \tt P = \dfrac{W}{t} \\\\ \star \: T.E = P.E + K.E \\\\\\ \underline{\tt Note}: \\ \circ \: \tt P.E = Potential Energy \\ \circ \: \tt K.E = Kinetic Energy \\ \circ \: \tt P = Power \\ \circ \: \tt t = Time taken \\ \circ \: \tt T.E = Total Energy \end{minipage}}$

$\rule{300}{1.5}$

Answer 2

☆Refer to the attachment please ☆