Question

A boy pushes a toy box 2.0 m along the floor by means of a
force of 10 N directed downward at an angle of 60° to the
horizontal. The work done by the boy is
(a) 6J
(b) 8J
(C) 10J
(d) 12 J​

Answer 1

We know that,

Work done = F*s*cos theta

so, W = 10*2*cos (60)

W = 10*2/2 = 10 J

hence, Option (C) is correct.