A boy read 3/4 th of the book on one day and 4/5 th of the remainder on another day. if there were 30 pages unread., how many pages did the book contain?
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Answered by
3
let the total pages be x.
therefore,according to the question,x-(3x/4+ 4x/5)=30
=>x-(15x+16x/20)= 30
=>20x-31x/20=30
=>11x=60
=>x=60/11
therefore the book had 60/11 pages
therefore,according to the question,x-(3x/4+ 4x/5)=30
=>x-(15x+16x/20)= 30
=>20x-31x/20=30
=>11x=60
=>x=60/11
therefore the book had 60/11 pages
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Answered by
1
Answer:
Let the total pages be 'x' in number.
According to condition 1:
3/8*x read on first day.
So remaining pages will be :
1-3/8*x
=5/8*x
According to condition 2:
Read 4/5 of remaining
So left unread =1/5 of remaining
Therefore remaining at last=1/5 * 5/8*x
=1/8x
Unread=30
Therefore:1/8*x = 30
>> X=240.
Therefore total page is240
Step-by-step explanation:
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