A boy read 3/8th of the book on one day and 4/5th of the remainder on another day. If three were 30 pages unread, how many pages did the book contain ?
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Answer:
Let the total pages be 'x' in number.
According to condition 1:
3/8*x read on first day.
So remaining pages will be :
1-3/8*x
=5/8*x
According to condition 2:
Read 4/5 of remaining
So left unread =1/5 of remaining
Therefore remaining at last=1/5 * 5/8*x
=1/8x
Unread=30
Therefore:1/8*x = 30
>> X=240.
Therefore total page is240
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