a boy read 3 by 8 of the book on one day and 4/5 of the remainder on another day if there were 30 pages unread , how many pages did the book contain?
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Answered by
28
he read 3/8 in 1st day
so remaining book=1-3/8=5/8
now he read 4/5 of remainder on another day =4/5(5/8)=4/8=1/2
so part of book he read in 2 days= 3/8+1/2=7/8
remaining book=1-7/8=1/8
according to question 1/8=30
so total no of pages =30*8=240pages Answer
so remaining book=1-3/8=5/8
now he read 4/5 of remainder on another day =4/5(5/8)=4/8=1/2
so part of book he read in 2 days= 3/8+1/2=7/8
remaining book=1-7/8=1/8
according to question 1/8=30
so total no of pages =30*8=240pages Answer
Pralove:
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Answered by
2
Answer:
Let the total pages be 'x' in number.
According to condition 1:
3/8*x read on first day.
So remaining pages will be :
1-3/8*x
=5/8*x
According to condition 2:
Read 4/5 of remaining
So left unread =1/5 of remaining
Therefore remaining at last=1/5 * 5/8*x
=1/8x
Unread=30
Therefore:1/8*x = 30
>> X=240.
Therefore total page is240
Step-by-step explanation:
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