A boy read three - eighth of the book on one day and for - fiveth of the remainder on anter day. If there were 30 pages unread,how many pages did the book contain
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Answered by
1
total pages be x
x-(3x/8)
=5x/8
(4/5)×(5x/8)
=x/2
(3x/8)+(x/2)
=7x/8
x-(7x/8)
=x/8
x/8=30
x=8×30
x=240
x-(3x/8)
=5x/8
(4/5)×(5x/8)
=x/2
(3x/8)+(x/2)
=7x/8
x-(7x/8)
=x/8
x/8=30
x=8×30
x=240
Answered by
0
Answer:
Let the total pages be 'x' in number.
According to condition 1:
3/8*x read on first day.
So remaining pages will be :
1-3/8*x
=5/8*x
According to condition 2:
Read 4/5 of remaining
So left unread =1/5 of remaining
Therefore remaining at last=1/5 * 5/8*x
=1/8x
Unread=30
Therefore:1/8*x = 30
>> X=240.
Therefore total page is240
Step-by-step explanation:
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