Question

A boy records that 4000 joule of work is required to transfer 10 coulomb of chargee between two points of a resistor of 50. The current passing through it is?

Answer 1

Answer:

The current passing through it is 8 A.

Explanation:

given:

work done   W = 4000 J

charge   q = 10 C

resistance    R = 50 Ω

we know that ,

W = V q

V = W/q

V = 4000 / 10

V = 400 V

According to Ohm's law,

current   I = V/R

             I = 400/50

             I = 8 A

therefore the current in the circuit is 8 A.

Hope it helps !

Answer 2

Given:

• Work done to transfer 10 C charge is 4000 Joule.

• Resistance in circuit is 50 Ohm.

To find:

• Current in circuit ?

Calculation:

First of all, let's find out the potential difference in the circuit across the resistor !

• Potential difference is defined as the amount of work done to transporter unit positive charge across two different points in an electric field.

Let potential difference be V :

$V = \dfrac{work}{charge}$

$\implies \:V = \dfrac{4000}{10}$

$\implies \:V =400 \: volt$

Now, the current in the circuit will be :

$i = \dfrac{V}{r}$

$\implies \: i = \dfrac{400}{50}$

$\implies \: i = 8 \: amp$

So, current in circuit is 8 Ampere .