Question

A boy records that 4000 joule of work is required to transfer 10coulumb of charge between two points of resistor of 50ohm the current passing through it is

Answer 1

Answer:

The current passing through the resistor is 8 ampere (A)

Explanation:

• Given :

Work done = 4000joules(J)

Charge = 10coulomb(C)

Resistance of the resistor = 50ohm(Ω)

• To find:

Current flowing through the resistor.

• Solution :

As we know potential difference (V) = work done(W) / charge (Q)

V = W/Q

P.D.= 4000J/10C

P.D.= 400V

(PD is potential difference)

As we know that,

potential difference(V) = current(I) × resistance(R)

P.D.(V)= IR

400V = I × 50Ω

400V/50Ω = I

I = 8 A (ampere)

Ans : The current passing through the resistor is 8 A (ampere).

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