Question

A boy records that 4000 joule of work is required to transfer 10 coulomb of charge between two points of a resistor of 50 ohm. the current passing through it is *
1 point
8 A
4 A
2 A
16 A ​

Answer 1

Answer:

Explanation:

first of all we find voltage (potential difference)

V=W/Q

W = 4000 joule

Q = 10 coulomb

V=4000/10

V=400 V

now, we apply ohm's law to find current

V=IR

V=400 V (from above)

R=50 OHM (given)

400=50 X I

I=400/50

I=8 A <= CURRENT