A boy released a ball from the top of a building.It will clear a window 2m hight at a distance 10m below the top in nearly
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Answered by
4
Answer:
it will come in 0.13
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Answered by
7
Answer:
the answer is 0.13 second
EXPLANATION:-
1st part
u=0
s=10m
v=?
taking acceralation= 9.8m/s²
v²-u²=2as
v²-0²=2×9.8×10
v²=196
v=14m/s²
Now,
for second part
s=2m (height of the window)
u=14m/s² (calculated above)
v=0
s= ut+1/2gt²
2=14t+1/2×9.8×t²
2=4.9t²+14t
0=4.9t²+14t-2
solving this equation, we get:-
t=0.13s approx.
hence time taken by the ball to clear the window is 0.13 second
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