A boy riding a bicycle with a speed of 4 m/s towards east direction, observes rain falling vertically downwards. If he increases his speed to 8 m/s, rain appears to meet him at 45° to the vertical. The speed of rain with respect to ground is-
a) 8 m/s
b) 4 m/s
c) 4√2 m/s
d) 2 m/s
Answers
Answered by
8
Answer:(c) 4root2
Explanation:
rain falling vertically downwards means horizontal compartment is 4m/s..
And for 45° the vertical component will also be 4m/s.
So by using pythagoras theorem u will get resultant of 4root2
javedsaif0:
yes..they will
both are same..only they change the sequence of questions..
no all the questions are different it is not like aiats
so your test timings must also be 8:30 to 11:30
no dude...my friends told me all questions are same
hmm...r8 timing
you gave the last 2 tests
only one test was conducted..on 22 march
and i missed a test of today
we had another test on 23rd it had the same syllabus
Answered by
3
Answer:
4√2 m/s
Explanation:
The horizontal component of the rain equals to the speed of the boy in the horizontal direction.
Velocity of rain in x direction is
V(rain-x dir) - V (boy) = V (rain wrt boy)
4 - 8 = -4 m/s
V (rain wrt boy) = 4 m/s in west
x component of rain is equal to the y component of rain.
Angle here is 45°
hence ground speed of rain will be 4√2 m/s.
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