A boy runs 100 m along the east then he turns to his left side at right angle and runs for 50m along the north direction find the distance and the magnitude of tje displacement of the boy ?
Answers
distance = 100 + 50 = 150 m
Displacement = √(100^2 + 50^2)
= √(10000 + 2500)
= √(12500)= √ 125 x 10 x 10
= 10√ 5 x 5 x 5 = 50√5 m
hope it helps
(i.) Therefore the distance traveled by the boy is 150 m.
(ii.) Therefore the magnitude of displacement traveled by the boy is 50√5 m.
Given:
The distance traveled by the boy in the east direction = 100 m
The distance traveled by the boy after turning left = 50 m
To Find:
The distance and displacement traveled by the boy.
Solution:
The given question can be solved as shown below.
Given that,
The distance traveled by the boy in the east direction = 100 m
The distance traveled by the boy after turning left = 50 m
(i.) The distance traveled by the boy:
The distance traveled by the boy = ( distance traveled in the east direction ) + ( distance traveled after turning left )
⇒ The distance traveled by the boy = 100 + 50 = 150 m
Therefore the distance traveled by the boy is 150 m.
(ii.) The magnitude of the displacement of the boy:
The magnitude of displacement of the boy = shortest distance traveled
By Pythagoras theorem,
⇒ displacement = √(100² + 50² ) = 50√5
Therefore the magnitude of displacement traveled by the boy is 50√5 m.
(i.) Therefore the distance traveled by the boy is 150 m.
(ii.) Therefore the magnitude of displacement traveled by the boy is 50√5 m.
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