Question

A boy runs around a square area of 500 m square. If he starts from a corner of the square , when will his displacement be maximum and minimum​

Answer 1

Answer:

Maximum displacement = 40 × 5^½ meters

Minimum displacement = 0 meters

Explanation:

We need to get the length of the square field given the area of the field.

Let the length of the square field be l.

The area of the field = l²

l² = 500

l = square root of 500

l = 10 square root of 5.

Note : Displacement = 0 if you move back to the same point.

At maximum displacement the displacement is equivalent to the perimeter of the square.

At minimum displacement the displacement = 0

Perimeter of the square = 4 × 10square root of 5 = 40 square root of 5

= 40(5)^½ meters is the maximum displacement.

Minimum displacement = 0