Question

a boy runs around the boundary of a square field of side 6 m in 10 seconds the displacement of the boy in one minute is

urgent pls tell fast ​

Answer 1

Answer:

360m

Explanation:

a boy runs around the boundary of a square field of side 6 m in 10 seconds the displacement of the boy in one minute is

a boy run in 10 seconds =6m

a boy run in one minute =

1 minute = 60 Seconds

so, 6*60 =360 m

Answer 2

Answer:

Explanation:

displacement = h^2= p^2+b^2

h^2 = 6^2+ 6^2

H^2 = 36+36

H^2= 72

H^2 = 2 Root 6

displacement = 2 root 6

time = 10 s

1s = 1/60 minutes  

= 0.7 minutes

displacement  in time  = 0.7 * 10

7/10*10 = 7 m

ans = 7m