Question

A boy runs first 100 m with a uniform speed of 8 m/s & the next 200 m with a uniform speed of 5 m/s. Calculate the average speed of the boy.

ans 5.71​​

Answer 1

Answer:

Therefore,

Time = 100 / 8

= 12.5 seconds

In second case,

The

The distance = 200m

The speed = 5 m / s

Therefore,

Time = 200 / 5

= 40 seconds

From the two cases,

Total distance = 200 + 300 = 500m

Total time = 12.5 + 40 = 52.5sec

Average speed = total distance / total time

= 500 / 52.5

9.52 m / s

Therefore,

The average speed for both situations is

9.25 meters per second.....

I hope this will help you.........

Answer 2

Answer: avg. speed = 7.27

Explanation: as we know that

D = S*T

in case 1

100 = 8 * T1

T1 = 100/8

in case 2

200 = 5* T2

T2 = 40

now

average speed = total distance / total time taken

avg. speed = 300/ 100/8 + 40

avg. speed = 2400/330

avg. speed = 7.27