A boy runs for 10 min. at a uniform speed of 9 km/hr. At what speed should he run for the next 20 min. so that the average speed comes 12 km/hr?
Answers
Answered by
749
Average speed (12km/hr) = Total Distance / Total Time
D1 + D2 / T1 + T2
Total Time = 10 min + 20 min = 30 min = 1/2 Hour
D1 = Speed * Time = 9 * 1/6 (10 min = 1/6 hr)
= 3/2 km = 1.5 km
D2 = ?
12 = 1.5 + D2 / 1/2
12 * 1/2 = 1.5 + D2
6 = 1.5 + D2
6 - 1.5 = D2
4.5 km = D2
Speed = Distance / Time
= 4.5 / 1/3 (20 min = 1/3 hr)
= 4.5 * 3 (Reciprocal)
= 13.5 km/hr
D1 + D2 / T1 + T2
Total Time = 10 min + 20 min = 30 min = 1/2 Hour
D1 = Speed * Time = 9 * 1/6 (10 min = 1/6 hr)
= 3/2 km = 1.5 km
D2 = ?
12 = 1.5 + D2 / 1/2
12 * 1/2 = 1.5 + D2
6 = 1.5 + D2
6 - 1.5 = D2
4.5 km = D2
Speed = Distance / Time
= 4.5 / 1/3 (20 min = 1/3 hr)
= 4.5 * 3 (Reciprocal)
= 13.5 km/hr
Answered by
347
Let us solve this in a different way.
Boy runs for first 10 min at 9 kmph = 9 km/hr
Let boy run for next 10 min at V kmph
let boy run for next 10 min at V kmph
His average speed is average of above three.
Average speed = (9+ 2 V) / 3 = 12 kmph
So 9 + 2 V = 3 * 12 = 36
2 V = 36 - 9 = 27
V = 27/2 = 13.5 km/hr
Boy runs for first 10 min at 9 kmph = 9 km/hr
Let boy run for next 10 min at V kmph
let boy run for next 10 min at V kmph
His average speed is average of above three.
Average speed = (9+ 2 V) / 3 = 12 kmph
So 9 + 2 V = 3 * 12 = 36
2 V = 36 - 9 = 27
V = 27/2 = 13.5 km/hr
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