A boy runs from point E to point F of a 150 m straight track in minute. He then turns around and runs back 60 m to point G in 40 s. What is (i) average speed (ii) average velocity of the boy between (a) E and F, (b) E and G
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Answer:
Take it as an example and solve your question by own
Explanation:
From pont A to B
Distance covered=300m
Displacement=300m
Time taken=2 min 30 sec=(2×60)+30=150 sec
Average speed=TimetakenDistance covered=150300=2 m/sec
Average velocity=TimetakenDisplacement=150300=2 m/sec
From point A to C
Distance covered=300+100=400m
Displacement=300−100=200m
Time taken=3 min 30 sec=(3×60)+30=210 sec
Average speed=TimetakenDistance covered=210400=1.90 m/sec
Average velocity=TimetakenDisplacement=210200=0.95 m/sec
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