A boy runs two times around a field , the length of which is 62 m and breadth is 40 m . Find distance covered by him .
Answers
If a boy runs two times around a field with dimensions 62 m x 40 m, then the distance covered by him is 408 m.
Step-by-step explanation:
The length of the rectangular field, l = 62 m
The breadth of the rectangular field, b = 40 m
∴ The perimeter of the rectangular field is given by
= 2 * [l + b]
= 2 * [62 + 40]
= 2 * 102
= 204 m
We know that the perimeter of the field is equal to the boy running 1 round around the field which is 204 m.
Thus,
The distance covered by him in running 2 rounds of the rectangular field is,
= 2 * 204
= 408 m
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Find
- We need to find the distance covered by the boy
Boy runs twice around field .
Length of field = 62m
breadth of filed = 40m
As only length breadth is given so, we can say that field is in the shape of rectangle.
we know that,
perimeter of rectangle = 2(length + breadth)
Hence,
Total distance travelled by boy is 408m