Math, asked by ikannu9435, 11 months ago

A boy runs two times around a field , the length of which is 62 m and breadth is 40 m . Find distance covered by him .

Answers

Answered by bhagyashreechowdhury
13

If a boy runs two times around a field with dimensions 62 m x 40 m, then the distance covered by him is 408 m.

Step-by-step explanation:

The length of the rectangular field, l = 62 m

The breadth of the rectangular field, b = 40 m

The perimeter of the rectangular field is given by

= 2 * [l + b]

= 2 * [62 + 40]

= 2 * 102

= 204 m

We know that the perimeter of the field is equal to the boy running 1 round around the field which is 204 m.

Thus,

The distance covered by him in running 2 rounds of the rectangular field is,

= 2 * 204

= 408 m

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Answered by MissAlison
8

{\fbox{\fbox{\huge\sf\pink{AnsWeR}}}}

Find

  • We need to find the distance covered by the boy

\underline{ \large \purple{ \mathscr{\dag\:A \bf{ccourding} \: to \: \mathscr {Q} \bf{uestion} }}}

Boy runs twice around field .

Length of field = 62m

breadth of filed = 40m

As only length breadth is given so, we can say that field is in the shape of rectangle.

we know that,

perimeter of rectangle = 2(length + breadth)

\sf\green{As\: the\: boy\: runs \:two\: times \:so,}

\sf\red{Distance \:travelled \:by\: boy = 2 × 2(l + b)}

\sf\blue{= 4(62 + 40)}

\sf\blue{= 4(102)}

\sf\blue{= 408m}

Hence,

Total distance travelled by boy is 408m

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