Question

A boy's age is one-fourth that of he father. After 24 years. The boy will be half the age of his father, find their present-ages​

Answer 1

Answer:

boy = 12y

father = 36y

Step-by-step explanation:

Boy's age = x

Father's age = 4x

After 24 years:

Boy = x + 24

Father = 4x +24

But father's age is twice that of Boy now.

so, 2(x+24) = 4x +24

=> 2x + 48 = 4x +24

=> 24 = 2x

x= 24/2 = 12

so, boy = 12 years

father = 36 years

Answer 2

Step-by-step explanation:

let be the boy age =x

His father age is =4x

Boy age =x+24

father age =4x+24

ATQ,

=2(x+24)=4x+24

=2x+48=4x+24

=4x-2x=48-24

=2x=24

=x=24÷2

=x=12

Boys age =x=12years

father age =4x=(4×12)=48

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