a boy's age is one fourth that of his father after 24 years the boy will be half the age of his father find their present age
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Answer:
Present age of the boy =x/4
Let present age of the father=x
x/4+24= x+24/2
(96+x/4)2=x+24
96+x= 2(x+24)
96-24= 2x-x
48=x
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Boys present age =x/4
present age of father = x
=> x/4+24 = x+24/2
=> (96+x)2 = 2(x+24)
4
=> (96+x) = 2x+24
=> x-2x = 24 - 96
=> -x = -48
=>[•°• minus - minus cancel]
=> x = 48
=> present age of father x = 48 yrs
=> present age of son x/4 = 48/4 =
12 yrs
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