a boy's age is one fourth that of his father after 24 years the boy will be half the age of his father find their present ages.
Answers
Answer:
let the Father Age= x
BOY AGE = 1/4 OF IT FATHER= X/4
SO EQUATION IS FORM
X/4+24=X/2
X+96/4=X/2
2X+192=4X
192=2X
X=192/2
X=96
HENCE BOY PRESENT AGE IS 24
HOW LONG AGE IS THAT BOY IS
ASK POSSIBLE ASWER
Answer:
Their present ages:
Boy's age = 12 years
His father's age = 48 years
Step-by-step explanation:
Given that:
A boy's age is one-fourth that of his father.
After 24 years the boy will be half the age of his father.
To Find:
Their present ages.
Let us assume:
Boy's present age be x.
His father's present age = 4x
After 24 years:
Boy's age = x + 24
Father's age = 4x + 24
Finding their present ages:
According to the question.
⟶ 2(x + 24) = 4x + 24
⟶ 2x + 48 = 4x + 24
⟶ 4x - 2x = 48 - 24
⟶ 2x = 24
⟶ x = 24/2
⟶ x = 12
Their present ages:
Boy's age = x = 12 years
His father's age = 4x = (4 × 12) = 48 years