Math, asked by sanikapol94, 16 hours ago

a boy's age is one fourth that of his father after 24 years the boy will be half the age of his father find their present ages.​

Answers

Answered by Sarthak0721
1

Answer:

let the Father Age= x

BOY AGE = 1/4 OF IT FATHER= X/4

SO EQUATION IS FORM

X/4+24=X/2

X+96/4=X/2

2X+192=4X

192=2X

X=192/2

X=96

HENCE BOY PRESENT AGE IS 24

HOW LONG AGE IS THAT BOY IS

ASK POSSIBLE ASWER

Answered by DotElixir
0

Answer:

Their present ages:

Boy's age = 12 years

His father's age = 48 years

Step-by-step explanation:

Given that:

A boy's age is one-fourth that of his father.

After 24 years the boy will be half the age of his father.

To Find:

Their present ages.

Let us assume:

Boy's present age be x.

His father's present age = 4x

After 24 years:

Boy's age = x + 24

Father's age = 4x + 24

Finding their present ages:

According to the question.

⟶ 2(x + 24) = 4x + 24

⟶ 2x + 48 = 4x + 24

⟶ 4x - 2x = 48 - 24

⟶ 2x = 24

⟶ x = 24/2

⟶ x = 12

Their present ages:

Boy's age = x = 12 years

His father's age = 4x = (4 × 12) = 48 years

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