Question

A boy save rupees 4.65 daily. Find the least number of days in which be will be able to save an exact number of rupees ​

Answer 1

Rs. 4.65 = 465 paise

The exact number of rupees will be a multiple of 100.

So, we have to find the LCM of 100 and 465.

100 = 2 × 2 ×5 × 5

465 = 3 × 5 × 31

LCM of 100 and 465 = 2 × 2 × 3 × 5 × 5 × 31 = 9300

So, the boy saves 9300 paise.

Hence, number of days required

= 9300/465

= 20 days