Question

A boy saves 45 paise daily. Then least number of days in which he will be able to save an exact number of rupees is

Answer 1

1 rupee = 100 paise
so to find least exact multiple of rupee we have to take LCM of 100 paise and 45 paise
So, LCM of 100 and 45 = 900

so, no. of days for saving 900 paise = 1 rupee is
900/45 = 20 days.

hope u like it.

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Answer 2

Concept Introduction:-

It might resemble a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that a boy saves $45$ paise daily.

To Find:-

We have to find that number of days in which he will be able to save an exact number of rupees.

Solution:-

According to the problem

$1$ rupee $= 100$ paise

so to find the least exact multiple of rupee we have to take LCM of $100$ paise and $45$ paise

So, LCM of $100$ and $45 = 900$

so, no. of days for saving $900$ paise $= 1$ rupee is

$900/45 = 20$ days.

Final Answer:-

The correct answer is $20$ days.

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