A boy saves RS 3.75 daily Find the least number of days in which he will be able to save an exact number of rupees.
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Answered by
0
theCorrect option is
B
20
Rs.4.65=465Paise
The exact number of rupees will be a multiple of 100
So, we have to fine the L.C.M. of 465 and 100
100=2×2×5×5
465=3×5×31
L.C.M. of 465 and 100=2×2×3×5×5×31=9300
So, the boy saves 9300 paise.
Hence, least number of days required to save 9300 paise =
465
9300
=20 days
Answered by
0
Answer:
12 days
Step-by-step explanation:
He will able to save an exact number of 45 rupees in 12 days.
37.5 ×12 = 45.00
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