Question

A boy saves RS 3.75 daily Find the least number of days in which he will be able to save an exact number of rupees.

Answer 1

theCorrect option is

B

20

Rs.4.65=465Paise

The exact number of rupees will be a multiple of 100

So, we have to fine the L.C.M. of 465 and 100

100=2×2×5×5

465=3×5×31

L.C.M. of 465 and 100=2×2×3×5×5×31=9300

So, the boy saves 9300 paise.

Hence, least number of days required to save 9300 paise =

465

9300

=20 days

Answer 2

Answer:

12 days

Step-by-step explanation:

He will able to save an exact number of 45 rupees in 12 days.

37.5 ×12 = 45.00