Math, asked by gaurimaheshpatil, 1 year ago

A boy sends 60% of his pocket money and has Rs.2 left. How much did he have first?

Answers

Answered by vishnu201
2

he had at first is rs.5


gaurimaheshpatil: how to solve?
vishnu201: 40=2. 100=? 100×2/40=x. x=5
Answered by shivang77
0

therefore the pocket money bof the Boy is Rs5

Attachments:

shivang77: after using 60% of his pocket money the money left is 40% and money left is to 2 rupees therefore 40% of the pocket money is rupees 2
gaurimaheshpatil: how to calculate the 40% left ?
shivang77: you have to just multiply 40 into X and divided by hundred
shivang77: SX is the total money and X/ 100 is its percentage of
Similar questions