A boy set 3 marks of each correct sum and lose 2 marks of each incorrect sums he does 24 sums and obtained 37 marks the number of correct sums were
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Correct Question:-
A boy get 3 marks of each correct sum and lose 2 marks of each incorrect sums, he does 24 sums and obtained 37 marks. Find the number of correct sums.
Answer:-
The number of correct sums is 17.
Given:
- A boy get 3 marks of each correct sum and lose 2 marks of each incorrect sums, he does 24 sums.
- He obtained 37 marks.
To find:
- Number of correct sums.
Solution:-
Let the number of correct sums be x and incorrect sums be y.
According to the first condition.
=> x+y=24...(1)
According to the second condition.
=> 3x-2y=37...(2)
Multiply equation (1) by 2, we get
=> 2x+2y=48...(3)
Add equations (2) and (3), we get
3x-2y=37
+
2x+2y=48
__________
5x=85
x=17
The number of correct sums is 17.
Answered by
30
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