Question

A boy spend 2 by 5 of his money and still h as rupee 45 left with him what did he have initially and how much did he spend

Answer 1

He spent 2/5 money,

therefore,
he have 3/5 money left.

ATQ, he have 45 rupees.

So,
The total money is 'x'.

(3/5)x = 45
x = (45×5)/3
x = 15×5

x = 75.

Therefore, Initial money = 75Rs.

Money he spent = 75-45 = 30Rs.

Please mark it as Brainliest, I've put much effort.

Answer 2

Concept Introduction:

If two out of five parts is spent by the boy he is left with three out of five parts of the total money he had.

Given: A boy spend $2$ by $5$ of his money and still h as rupee $45$ left with him.

To Find:

We have to find the value of, total money he had initially.

Solution:

According to the problem,

Let the boy had x Rs.

∴$3x/5=45$

⇒$x=75$ Rs.

Final Answer:

The value of total amount of money boy had is Rs. $75$.

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